C++ Program to check whether a String or a Number is Palindrome using function overloading

The following C++ program uses function overloading to check if the entered string or number is palindrome using a overloaded function 'pal'.The function is overloaded by specifying two variants of attributes , the first one an integer for Number Palindrome and the second a character array for String Palindrome.
1)void pal(int n) 2)void pal(char a[])
The Complete Source Code is Provided Below.If you have any queries, Just comment on this Post.

 #include<iostream.h>  
 #include<conio.h>  
 #include<stdio.h>  
 #include<string.h>  
 //c-madeeasy.blogspot.com  
 void pal(char a[])  
 {  
 int i,j,l=0;  
 l=strlen(a);  
 int f=0;  
 for(i=0,l=l-1;a[i]!='\0';i++,l--)  
 {  
 if(a[i]!=a[l])  
 {  
 f=1;  
 break;  
 }  
 }  
 if(f==1)  
 {  
 printf("NoN Palindrome");  
 }  
 else if(f==0)  
 printf("Palindome");  
 }  
 void pal(int n)  
 {  
 int a,s=0,d;  
  a=n;  
 while(n>0)  
 {  
 d=n%10;  
 s=s*10+d;  
 n=n/10;  
 }  
 if(a==s)  
 cout<<"Palindrome";  
 else  
 cout<<"Non Palindrome";  
 }  
 void main()  
 {  
 clrscr();  
 int c=0;  
 do  
 {  
 cout<<"\n1.String Palindrome 2.Number Palindrome 3.Quit";  
 cout<<"\nEnter Choice: ";  
 cin>>c;  
 switch(c)  
 {  
 case 1:  
 cout<<"Enter the String: ";  
 char a[20];  
 cin>>a;  
 pal(a);  
 break;  
 case 2:  
 cout<<"Enter the Number: ";  
 int t;  
 cin>>t;  
 pal(t);  
 break;  
 case 3:  
 break;  
 default:  
 break;  
 }  
 }while (c!=3);  
 }